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Distinct Linear Factors, Example 3: Calculus—Integrals: Partial Fractions

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Item number
75234
Description
Partial fractions, or partial fractions decomposition, is a way to evaluate integrals of rational functions. There are four types of factors you need to deal with when you're working through a partial fractions decomposition: Distinct linear factors Repeated linear factors Distinct quadratic factors Repeated quadratic factors You may also have a combination of these types of factors. This video is an example of how to use partial fractions when you're dealing with distinct linear factors.

Distinct Linear Factors, Example 2: Calculus—Integrals: Partial Fractions

Submitted by Anonymous on
Item number
75233
Description
Partial fractions, or partial fractions decomposition, is a way to evaluate integrals of rational functions. There are four types of factors you need to deal with when you're working through a partial fractions decomposition: Distinct linear factors Repeated linear factors Distinct quadratic factors Repeated quadratic factors You may also have a combination of these types of factors. This video is an example of how to use partial fractions when you're dealing with distinct linear factors.

Tabular Integration: Calculus—Integrals: Integration by Parts

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Item number
75232
Description
Tabular integration is an alternative method to integration by parts, most commonly used when part of the function you're trying to integrate is a power function. Since tabular integration can't always be used, where integration by parts can, this method isn't usually taught.

U-Substitution in Definite Integrals: Calculus—Integrals: U-Substitution

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Item number
75231
Description
When you use substitution in definite integrals, you have two options for dealing with the limits of integration. When you make the substitution, change the limits of integration so that they're associated with the substitution variable, instead of with the original variable. If you do this, you'll be able to plug the new limits of integration directly into the integrated function. When you make the substitution, leave the limits of integration in terms of the original variable. If you do this, you'll have to back-substitute to get the integration in terms of the original variable before evaluating over the limits of integration.